Base | Representation |
---|---|
bin | 100000001000110010010110… |
… | …101100111101000000101011 |
3 | 200112110002122001200022200122 |
4 | 200020302112230331000223 |
5 | 122011214001402042103 |
6 | 1220335145153153455 |
7 | 41525400322266311 |
oct | 4010622654750053 |
9 | 615402561608618 |
10 | 141341312143403 |
11 | 41043571a43209 |
12 | 13a28a8755b88b |
13 | 60b35756876b8 |
14 | 26c8d554060b1 |
15 | 115192a1d6b38 |
hex | 808c96b3d02b |
141341312143403 has 2 divisors, whose sum is σ = 141341312143404. Its totient is φ = 141341312143402.
The previous prime is 141341312143379. The next prime is 141341312143411. The reversal of 141341312143403 is 304341213143141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141341312143403 - 28 = 141341312143147 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (141341312143903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70670656071701 + 70670656071702.
It is an arithmetic number, because the mean of its divisors is an integer number (70670656071702).
Almost surely, 2141341312143403 is an apocalyptic number.
141341312143403 is a deficient number, since it is larger than the sum of its proper divisors (1).
141341312143403 is an equidigital number, since it uses as much as digits as its factorization.
141341312143403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 141341312143403 its reverse (304341213143141), we get a palindrome (445682525286544).
The spelling of 141341312143403 in words is "one hundred forty-one trillion, three hundred forty-one billion, three hundred twelve million, one hundred forty-three thousand, four hundred three".
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