Base | Representation |
---|---|
bin | 11010010100111011… |
… | …10101010100000111 |
3 | 1100111001001121022220 |
4 | 31022131311110013 |
5 | 212421331031143 |
6 | 10254305423423 |
7 | 1010155012236 |
oct | 151235652407 |
9 | 40431047286 |
10 | 14134236423 |
11 | 5aa345402a |
12 | 28a563ab73 |
13 | 144337ba08 |
14 | 98125ab1d |
15 | 57acebd83 |
hex | 34a775507 |
14134236423 has 4 divisors (see below), whose sum is σ = 18845648568. Its totient is φ = 9422824280.
The previous prime is 14134236419. The next prime is 14134236499. The reversal of 14134236423 is 32463243141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14134236423 - 22 = 14134236419 is a prime.
It is a super-3 number, since 3×141342364233 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14134237423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355706068 + ... + 2355706073.
It is an arithmetic number, because the mean of its divisors is an integer number (4711412142).
Almost surely, 214134236423 is an apocalyptic number.
14134236423 is a deficient number, since it is larger than the sum of its proper divisors (4711412145).
14134236423 is an equidigital number, since it uses as much as digits as its factorization.
14134236423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4711412144.
The product of its digits is 41472, while the sum is 33.
Adding to 14134236423 its reverse (32463243141), we get a palindrome (46597479564).
The spelling of 14134236423 in words is "fourteen billion, one hundred thirty-four million, two hundred thirty-six thousand, four hundred twenty-three".
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