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14134236423 = 34711412141
BaseRepresentation
bin11010010100111011…
…10101010100000111
31100111001001121022220
431022131311110013
5212421331031143
610254305423423
71010155012236
oct151235652407
940431047286
1014134236423
115aa345402a
1228a563ab73
13144337ba08
1498125ab1d
1557acebd83
hex34a775507

14134236423 has 4 divisors (see below), whose sum is σ = 18845648568. Its totient is φ = 9422824280.

The previous prime is 14134236419. The next prime is 14134236499. The reversal of 14134236423 is 32463243141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14134236423 - 22 = 14134236419 is a prime.

It is a super-3 number, since 3×141342364233 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14134237423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355706068 + ... + 2355706073.

It is an arithmetic number, because the mean of its divisors is an integer number (4711412142).

Almost surely, 214134236423 is an apocalyptic number.

14134236423 is a deficient number, since it is larger than the sum of its proper divisors (4711412145).

14134236423 is an equidigital number, since it uses as much as digits as its factorization.

14134236423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4711412144.

The product of its digits is 41472, while the sum is 33.

Adding to 14134236423 its reverse (32463243141), we get a palindrome (46597479564).

The spelling of 14134236423 in words is "fourteen billion, one hundred thirty-four million, two hundred thirty-six thousand, four hundred twenty-three".

Divisors: 1 3 4711412141 14134236423