Base | Representation |
---|---|
bin | 100000001000110011011110… |
… | …001000011100110110000111 |
3 | 200112110012201120122212120102 |
4 | 200020303132020130312013 |
5 | 122011223430144042043 |
6 | 1220335504122554315 |
7 | 41525442113402441 |
oct | 4010633610346607 |
9 | 615405646585512 |
10 | 141342510534023 |
11 | 4104402744a887 |
12 | 13a2916096899b |
13 | 60b3706a37486 |
14 | 26c902a637491 |
15 | 115199a5056b8 |
hex | 808cde21cd87 |
141342510534023 has 4 divisors (see below), whose sum is σ = 146216390207640. Its totient is φ = 136468630860408.
The previous prime is 141342510534019. The next prime is 141342510534031. The reversal of 141342510534023 is 320435015243141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 141342510534023 - 22 = 141342510534019 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141342510534223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2436939836765 + ... + 2436939836822.
It is an arithmetic number, because the mean of its divisors is an integer number (36554097551910).
Almost surely, 2141342510534023 is an apocalyptic number.
141342510534023 is a deficient number, since it is larger than the sum of its proper divisors (4873879673617).
141342510534023 is an equidigital number, since it uses as much as digits as its factorization.
141342510534023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4873879673616.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 141342510534023 its reverse (320435015243141), we get a palindrome (461777525777164).
The spelling of 141342510534023 in words is "one hundred forty-one trillion, three hundred forty-two billion, five hundred ten million, five hundred thirty-four thousand, twenty-three".
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