141343014431011 has 4 divisors (see below), whose sum is σ = 144009863759952. Its totient is φ = 138676165102072.

The previous prime is 141343014430973. The next prime is 141343014431023. The reversal of 141343014431011 is 110134410343141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141343014431011 - 2⁷ = 141343014430883 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141343014431711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1333424664391 + ... + 1333424664496.

It is an arithmetic number, because the mean of its divisors is an integer number (36002465939988).

Almost surely, 2^{141343014431011} is an apocalyptic number.

141343014431011 is a deficient number, since it is larger than the sum of its proper divisors (2666849328941).

141343014431011 is an equidigital number, since it uses as much as digits as its factorization.

141343014431011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2666849328940.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 141343014431011 its reverse (110134410343141), we get a palindrome (251477424774152).

The spelling of 141343014431011 in words is "one hundred forty-one trillion, three hundred forty-three billion, fourteen million, four hundred thirty-one thousand, eleven".