Base | Representation |
---|---|
bin | 11010010100111100… |
… | …11101101001110011 |
3 | 1100111001100222222110 |
4 | 31022132131221303 |
5 | 212421401323101 |
6 | 10254313140403 |
7 | 1010156301036 |
oct | 151236355163 |
9 | 40431328873 |
10 | 14134401651 |
11 | 5aa3557187 |
12 | 28a56ba703 |
13 | 1443408c96 |
14 | 9812a101d |
15 | 57ad30cd6 |
hex | 34a79da73 |
14134401651 has 4 divisors (see below), whose sum is σ = 18845868872. Its totient is φ = 9422934432.
The previous prime is 14134401649. The next prime is 14134401653. The reversal of 14134401651 is 15610443141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15610443141 = 3 ⋅5203481047.
It is an interprime number because it is at equal distance from previous prime (14134401649) and next prime (14134401653).
It is not a de Polignac number, because 14134401651 - 21 = 14134401649 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14134401653) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2355733606 + ... + 2355733611.
It is an arithmetic number, because the mean of its divisors is an integer number (4711467218).
Almost surely, 214134401651 is an apocalyptic number.
14134401651 is a deficient number, since it is larger than the sum of its proper divisors (4711467221).
14134401651 is an equidigital number, since it uses as much as digits as its factorization.
14134401651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4711467220.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 14134401651 its reverse (15610443141), we get a palindrome (29744844792).
The spelling of 14134401651 in words is "fourteen billion, one hundred thirty-four million, four hundred one thousand, six hundred fifty-one".
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