141344111024201 has 4 divisors (see below), whose sum is σ = 147489507155712. Its totient is φ = 135198714892692.

The previous prime is 141344111024197. The next prime is 141344111024209. The reversal of 141344111024201 is 102420111443141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141344111024201 - 2² = 141344111024197 is a prime.

It is a super-3 number, since 3×141344111024201³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141344111024209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3072698065721 + ... + 3072698065766.

It is an arithmetic number, because the mean of its divisors is an integer number (36872376788928).

Almost surely, 2^{141344111024201} is an apocalyptic number.

It is an amenable number.

141344111024201 is a deficient number, since it is larger than the sum of its proper divisors (6145396131511).

141344111024201 is an equidigital number, since it uses as much as digits as its factorization.

141344111024201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6145396131510.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 141344111024201 its reverse (102420111443141), we get a palindrome (243764222467342).

The spelling of 141344111024201 in words is "one hundred forty-one trillion, three hundred forty-four billion, one hundred eleven million, twenty-four thousand, two hundred one".