141352510305133 has 2 divisors, whose sum is σ = 141352510305134. Its totient is φ = 141352510305132.

The previous prime is 141352510305113. The next prime is 141352510305187. The reversal of 141352510305133 is 331503015253141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125571253516164 + 15781256788969 = 11205858^2 + 3972563^2 .

It is an emirp because it is prime and its reverse (331503015253141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141352510305133 - 2¹³ = 141352510296941 is a prime.

It is a super-2 number, since 2×141352510305133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141352510305092 and 141352510305101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141352510305113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70676255152566 + 70676255152567.

It is an arithmetic number, because the mean of its divisors is an integer number (70676255152567).

Almost surely, 2^{141352510305133} is an apocalyptic number.

It is an amenable number.

141352510305133 is a deficient number, since it is larger than the sum of its proper divisors (1).

141352510305133 is an equidigital number, since it uses as much as digits as its factorization.

141352510305133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81000, while the sum is 37.

Adding to 141352510305133 its reverse (331503015253141), we get a palindrome (472855525558274).

The spelling of 141352510305133 in words is "one hundred forty-one trillion, three hundred fifty-two billion, five hundred ten million, three hundred five thousand, one hundred thirty-three".