1413700125403 has 4 divisors (see below), whose sum is σ = 1413851348800. Its totient is φ = 1413548902008.

The previous prime is 1413700125401. The next prime is 1413700125433. The reversal of 1413700125403 is 3045210073141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1413700125403 - 2¹ = 1413700125401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1413700125401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75597675 + ... + 75616372.

It is an arithmetic number, because the mean of its divisors is an integer number (353462837200).

Almost surely, 2^{1413700125403} is an apocalyptic number.

1413700125403 is a deficient number, since it is larger than the sum of its proper divisors (151223397).

1413700125403 is an equidigital number, since it uses as much as digits as its factorization.

1413700125403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 151223396.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 1413700125403 its reverse (3045210073141), we get a palindrome (4458910198544).

The spelling of 1413700125403 in words is "one trillion, four hundred thirteen billion, seven hundred million, one hundred twenty-five thousand, four hundred three".