Base | Representation |
---|---|
bin | 10100100100101111011… |
… | …001100000010001010001 |
3 | 12000011100220100222010212 |
4 | 110210233121200101101 |
5 | 141131020400032223 |
6 | 3001301530133505 |
7 | 204101155040165 |
oct | 24445731402121 |
9 | 5004326328125 |
10 | 1413839455313 |
11 | 4a567357196a |
12 | 1aa017b81295 |
13 | a342ab9439c |
14 | 4c604650ca5 |
15 | 26b9d12e278 |
hex | 1492f660451 |
1413839455313 has 2 divisors, whose sum is σ = 1413839455314. Its totient is φ = 1413839455312.
The previous prime is 1413839455291. The next prime is 1413839455337. The reversal of 1413839455313 is 3135549383141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1368635592769 + 45203862544 = 1169887^2 + 212612^2 .
It is a cyclic number.
It is not a de Polignac number, because 1413839455313 - 212 = 1413839451217 is a prime.
It is not a weakly prime, because it can be changed into another prime (1413839452313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706919727656 + 706919727657.
It is an arithmetic number, because the mean of its divisors is an integer number (706919727657).
Almost surely, 21413839455313 is an apocalyptic number.
It is an amenable number.
1413839455313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413839455313 is an equidigital number, since it uses as much as digits as its factorization.
1413839455313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2332800, while the sum is 50.
The spelling of 1413839455313 in words is "one trillion, four hundred thirteen billion, eight hundred thirty-nine million, four hundred fifty-five thousand, three hundred thirteen".
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