Base | Representation |
---|---|
bin | 10100100100111000111… |
… | …111111101011010110001 |
3 | 12000011210010110110121112 |
4 | 110210320333331122301 |
5 | 141131333113443441 |
6 | 3001325522403105 |
7 | 204105152130023 |
oct | 24447077753261 |
9 | 5004703413545 |
10 | 1414000531121 |
11 | 4a5746489572 |
12 | 1aa061b00495 |
13 | a3455370709 |
14 | 4c61bbc0013 |
15 | 26bac34a4eb |
hex | 14938ffd6b1 |
1414000531121 has 4 divisors (see below), whose sum is σ = 1414102118244. Its totient is φ = 1413898944000.
The previous prime is 1414000531003. The next prime is 1414000531189. The reversal of 1414000531121 is 1211350004141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 498746688400 + 915253842721 = 706220^2 + 956689^2 .
It is a cyclic number.
It is not a de Polignac number, because 1414000531121 - 210 = 1414000530097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1414000531421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50772680 + ... + 50800521.
It is an arithmetic number, because the mean of its divisors is an integer number (353525529561).
Almost surely, 21414000531121 is an apocalyptic number.
It is an amenable number.
1414000531121 is a deficient number, since it is larger than the sum of its proper divisors (101587123).
1414000531121 is a wasteful number, since it uses less digits than its factorization.
1414000531121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101587122.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 1414000531121 its reverse (1211350004141), we get a palindrome (2625350535262).
The spelling of 1414000531121 in words is "one trillion, four hundred fourteen billion, five hundred thirty-one thousand, one hundred twenty-one".
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