141401244032311 has 4 divisors (see below), whose sum is σ = 142722750985992. Its totient is φ = 140079737078632.

The previous prime is 141401244032287. The next prime is 141401244032327. The reversal of 141401244032311 is 113230442104141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141401244032311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141401244032371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660753476680 + ... + 660753476893.

It is an arithmetic number, because the mean of its divisors is an integer number (35680687746498).

Almost surely, 2^{141401244032311} is an apocalyptic number.

141401244032311 is a deficient number, since it is larger than the sum of its proper divisors (1321506953681).

141401244032311 is a wasteful number, since it uses less digits than its factorization.

141401244032311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1321506953680.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 141401244032311 its reverse (113230442104141), we get a palindrome (254631686136452).

The spelling of 141401244032311 in words is "one hundred forty-one trillion, four hundred one billion, two hundred forty-four million, thirty-two thousand, three hundred eleven".