1414043314132 has 24 divisors (see below), whose sum is σ = 2516769208800. Its totient is φ = 695067278880.

The previous prime is 1414043314121. The next prime is 1414043314133. The reversal of 1414043314132 is 2314133404141.

It is a junction number, because it is equal to n+sod(n) for n = 1414043314094 and 1414043314103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1414043314133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12554007 + ... + 12666142.

It is an arithmetic number, because the mean of its divisors is an integer number (104865383700).

Almost surely, 2^{1414043314132} is an apocalyptic number.

It is an amenable number.

1414043314132 is a deficient number, since it is larger than the sum of its proper divisors (1102725894668).

1414043314132 is a wasteful number, since it uses less digits than its factorization.

1414043314132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25220391 (or 25220389 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1414043314132 its reverse (2314133404141), we get a palindrome (3728176718273).

Subtracting 1414043314132 from its reverse (2314133404141), we obtain a palindrome (900090090009).

The spelling of 1414043314132 in words is "one trillion, four hundred fourteen billion, forty-three million, three hundred fourteen thousand, one hundred thirty-two".