Base | Representation |
---|---|
bin | 11010010101101011… |
… | …11000100101000011 |
3 | 1100111110220220221001 |
4 | 31022311320211003 |
5 | 212424434310001 |
6 | 10255052512431 |
7 | 1010262421534 |
oct | 151265704503 |
9 | 40443826831 |
10 | 14140541251 |
11 | 5aa6a6aa31 |
12 | 28a777b717 |
13 | 1444778695 |
14 | 98201c68b |
15 | 57b645001 |
hex | 34ad78943 |
14140541251 has 2 divisors, whose sum is σ = 14140541252. Its totient is φ = 14140541250.
The previous prime is 14140541183. The next prime is 14140541257. The reversal of 14140541251 is 15214504141.
14140541251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (15214504141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14140541251 - 213 = 14140533059 is a prime.
It is not a weakly prime, because it can be changed into another prime (14140541257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7070270625 + 7070270626.
It is an arithmetic number, because the mean of its divisors is an integer number (7070270626).
Almost surely, 214140541251 is an apocalyptic number.
14140541251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14140541251 is an equidigital number, since it uses as much as digits as its factorization.
14140541251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3200, while the sum is 28.
The spelling of 14140541251 in words is "fourteen billion, one hundred forty million, five hundred forty-one thousand, two hundred fifty-one".
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