Base | Representation |
---|---|
bin | 10100100100111100111… |
… | …111101101010110011001 |
3 | 12000011221210121121101101 |
4 | 110210330333231112121 |
5 | 141132002244333134 |
6 | 3001340315351401 |
7 | 204106625026555 |
oct | 24447477552631 |
9 | 5004853547341 |
10 | 1414067574169 |
11 | 4a578030aa48 |
12 | 1aa080452561 |
13 | a3466215363 |
14 | 4c626a72865 |
15 | 26bb318ee14 |
hex | 1493cfed599 |
1414067574169 has 2 divisors, whose sum is σ = 1414067574170. Its totient is φ = 1414067574168.
The previous prime is 1414067574119. The next prime is 1414067574203. The reversal of 1414067574169 is 9614757604141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1403762888025 + 10304686144 = 1184805^2 + 101512^2 .
It is a cyclic number.
It is not a de Polignac number, because 1414067574169 - 215 = 1414067541401 is a prime.
It is a super-2 number, since 2×14140675741692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1414067574119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707033787084 + 707033787085.
It is an arithmetic number, because the mean of its divisors is an integer number (707033787085).
Almost surely, 21414067574169 is an apocalyptic number.
It is an amenable number.
1414067574169 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414067574169 is an equidigital number, since it uses as much as digits as its factorization.
1414067574169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 55.
The spelling of 1414067574169 in words is "one trillion, four hundred fourteen billion, sixty-seven million, five hundred seventy-four thousand, one hundred sixty-nine".
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