Base | Representation |
---|---|
bin | 10100100100111100111… |
… | …111101101010101100111 |
3 | 12000011221210121121022112 |
4 | 110210330333231111213 |
5 | 141132002244332434 |
6 | 3001340315351235 |
7 | 204106625026454 |
oct | 24447477552547 |
9 | 5004853547275 |
10 | 1414067574119 |
11 | 4a578030aa02 |
12 | 1aa08045251b |
13 | a3466215325 |
14 | 4c626a7282b |
15 | 26bb318edce |
hex | 1493cfed567 |
1414067574119 has 2 divisors, whose sum is σ = 1414067574120. Its totient is φ = 1414067574118.
The previous prime is 1414067574113. The next prime is 1414067574169. The reversal of 1414067574119 is 9114757604141.
It is an a-pointer prime, because the next prime (1414067574169) can be obtained adding 1414067574119 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1414067574119 - 216 = 1414067508583 is a prime.
It is a super-2 number, since 2×14140675741192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1414067574113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707033787059 + 707033787060.
It is an arithmetic number, because the mean of its divisors is an integer number (707033787060).
Almost surely, 21414067574119 is an apocalyptic number.
1414067574119 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414067574119 is an equidigital number, since it uses as much as digits as its factorization.
1414067574119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 846720, while the sum is 50.
The spelling of 1414067574119 in words is "one trillion, four hundred fourteen billion, sixty-seven million, five hundred seventy-four thousand, one hundred nineteen".
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