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1414110431003 is a prime number
BaseRepresentation
bin10100100100111111100…
…011001100011100011011
312000012001210020221220112
4110210333203030130123
5141132044232243003
63001344450114535
7204110655223604
oct24447743143433
95005053227815
101414110431003
114a57a2521a16
121aa09287ba4b
13a347206c32a
144c62c62adab
1526bb6d083d8
hex1493f8cc71b

1414110431003 has 2 divisors, whose sum is σ = 1414110431004. Its totient is φ = 1414110431002.

The previous prime is 1414110430961. The next prime is 1414110431009. The reversal of 1414110431003 is 3001340114141.

It is a strong prime.

It is an emirp because it is prime and its reverse (3001340114141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1414110431003 - 26 = 1414110430939 is a prime.

It is a super-2 number, since 2×14141104310032 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1414110431003.

It is not a weakly prime, because it can be changed into another prime (1414110431009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707055215501 + 707055215502.

It is an arithmetic number, because the mean of its divisors is an integer number (707055215502).

Almost surely, 21414110431003 is an apocalyptic number.

1414110431003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414110431003 is an equidigital number, since it uses as much as digits as its factorization.

1414110431003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1414110431003 its reverse (3001340114141), we get a palindrome (4415450545144).

The spelling of 1414110431003 in words is "one trillion, four hundred fourteen billion, one hundred ten million, four hundred thirty-one thousand, three".