1414133131011 has 4 divisors (see below), whose sum is σ = 1885510841352. Its totient is φ = 942755420672.

The previous prime is 1414133131009. The next prime is 1414133131039. The reversal of 1414133131011 is 1101313314141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1414133131011 - 2¹ = 1414133131009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1414133131001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235688855166 + ... + 235688855171.

It is an arithmetic number, because the mean of its divisors is an integer number (471377710338).

Almost surely, 2^{1414133131011} is an apocalyptic number.

1414133131011 is a deficient number, since it is larger than the sum of its proper divisors (471377710341).

1414133131011 is an equidigital number, since it uses as much as digits as its factorization.

1414133131011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 471377710340.

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 1414133131011 its reverse (1101313314141), we get a palindrome (2515446445152).

The spelling of 1414133131011 in words is "one trillion, four hundred fourteen billion, one hundred thirty-three million, one hundred thirty-one thousand, eleven".