Base | Representation |
---|---|
bin | 10100100101000000111… |
… | …110010000010111001001 |
3 | 12000012010110011201222012 |
4 | 110211000332100113021 |
5 | 141132121340132103 |
6 | 3001351101505305 |
7 | 204111365145026 |
oct | 24450076202711 |
9 | 5005113151865 |
10 | 1414134302153 |
11 | 4a5804a46741 |
12 | 1aa09a872235 |
13 | a3476ca9781 |
14 | 4c63188254d |
15 | 26bb8e712d8 |
hex | 14940f905c9 |
1414134302153 has 2 divisors, whose sum is σ = 1414134302154. Its totient is φ = 1414134302152.
The previous prime is 1414134302131. The next prime is 1414134302159. The reversal of 1414134302153 is 3512034314141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1016128513024 + 398005789129 = 1008032^2 + 630877^2 .
It is a cyclic number.
It is not a de Polignac number, because 1414134302153 - 218 = 1414134040009 is a prime.
It is not a weakly prime, because it can be changed into another prime (1414134302159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707067151076 + 707067151077.
It is an arithmetic number, because the mean of its divisors is an integer number (707067151077).
Almost surely, 21414134302153 is an apocalyptic number.
It is an amenable number.
1414134302153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414134302153 is an equidigital number, since it uses as much as digits as its factorization.
1414134302153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 1414134302153 its reverse (3512034314141), we get a palindrome (4926168616294).
The spelling of 1414134302153 in words is "one trillion, four hundred fourteen billion, one hundred thirty-four million, three hundred two thousand, one hundred fifty-three".
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