141420401201 has 2 divisors, whose sum is σ = 141420401202. Its totient is φ = 141420401200.

The previous prime is 141420401197. The next prime is 141420401203. The reversal of 141420401201 is 102104024141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110742528400 + 30677872801 = 332780^2 + 175151^2 .

It is a cyclic number.

It is not a de Polignac number, because 141420401201 - 2² = 141420401197 is a prime.

Together with 141420401203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (141420401203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70710200600 + 70710200601.

It is an arithmetic number, because the mean of its divisors is an integer number (70710200601).

Almost surely, 2^141420401201 is an apocalyptic number.

It is an amenable number.

141420401201 is a deficient number, since it is larger than the sum of its proper divisors (1).

141420401201 is an equidigital number, since it uses as much as digits as its factorization.

141420401201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 20.

Adding to 141420401201 its reverse (102104024141), we get a palindrome (243524425342).

The spelling of 141420401201 in words is "one hundred forty-one billion, four hundred twenty million, four hundred one thousand, two hundred one".