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14142041103 = 34714013701
BaseRepresentation
bin11010010101110111…
…00110110000001111
31100111120202010100010
431022323212300033
5212430330303403
610255145004303
71010311236351
oct151273466017
940446663303
1014142041103
115aa78a4883
1228a8183693
131444b82278
149822cd0d1
1557b83e603
hex34aee6c0f

14142041103 has 4 divisors (see below), whose sum is σ = 18856054808. Its totient is φ = 9428027400.

The previous prime is 14142041083. The next prime is 14142041113. The reversal of 14142041103 is 30114024141.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14142041103 - 213 = 14142032911 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14142041103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14142041113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2357006848 + ... + 2357006853.

It is an arithmetic number, because the mean of its divisors is an integer number (4714013702).

Almost surely, 214142041103 is an apocalyptic number.

14142041103 is a deficient number, since it is larger than the sum of its proper divisors (4714013705).

14142041103 is an equidigital number, since it uses as much as digits as its factorization.

14142041103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4714013704.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14142041103 its reverse (30114024141), we get a palindrome (44256065244).

The spelling of 14142041103 in words is "fourteen billion, one hundred forty-two million, forty-one thousand, one hundred three".

Divisors: 1 3 4714013701 14142041103