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14142344332307 is a prime number
BaseRepresentation
bin1100110111001100010101…
…1010010000010000010011
31212001222212021220020212012
43031303011122100100103
53323202010122113212
650024523040053135
72656515322251662
oct315630532202023
955058767806765
1014142344332307
11456280975a344
121704a6a6041ab
137b7804410809
1436c6c9188dd9
15197d1c84b922
hexcdcc5690413

14142344332307 has 2 divisors, whose sum is σ = 14142344332308. Its totient is φ = 14142344332306.

The previous prime is 14142344332271. The next prime is 14142344332309. The reversal of 14142344332307 is 70323344324141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14142344332307 - 236 = 14073624855571 is a prime.

It is a super-3 number, since 3×141423443323073 (a number of 40 digits) contains 333 as substring.

Together with 14142344332309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14142344332309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7071172166153 + 7071172166154.

It is an arithmetic number, because the mean of its divisors is an integer number (7071172166154).

Almost surely, 214142344332307 is an apocalyptic number.

14142344332307 is a deficient number, since it is larger than the sum of its proper divisors (1).

14142344332307 is an equidigital number, since it uses as much as digits as its factorization.

14142344332307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 580608, while the sum is 41.

Adding to 14142344332307 its reverse (70323344324141), we get a palindrome (84465688656448).

The spelling of 14142344332307 in words is "fourteen trillion, one hundred forty-two billion, three hundred forty-four million, three hundred thirty-two thousand, three hundred seven".