Base | Representation |
---|---|
bin | 10100100101001000000… |
… | …000001101100010110011 |
3 | 12000012102200010101102101 |
4 | 110211020000031202303 |
5 | 141132342034133121 |
6 | 3001410514001231 |
7 | 204114326553052 |
oct | 24451000154263 |
9 | 5005380111371 |
10 | 1414252255411 |
11 | 4a586558a776 |
12 | 1aa112276217 |
13 | a3495567bb8 |
14 | 4c6433c8399 |
15 | 26bc44c0491 |
hex | 1494800d8b3 |
1414252255411 has 2 divisors, whose sum is σ = 1414252255412. Its totient is φ = 1414252255410.
The previous prime is 1414252255309. The next prime is 1414252255417. The reversal of 1414252255411 is 1145522524141.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1145522524141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1414252255411 - 223 = 1414243866803 is a prime.
It is not a weakly prime, because it can be changed into another prime (1414252255417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707126127705 + 707126127706.
It is an arithmetic number, because the mean of its divisors is an integer number (707126127706).
Almost surely, 21414252255411 is an apocalyptic number.
1414252255411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414252255411 is an equidigital number, since it uses as much as digits as its factorization.
1414252255411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 64000, while the sum is 37.
Adding to 1414252255411 its reverse (1145522524141), we get a palindrome (2559774779552).
The spelling of 1414252255411 in words is "one trillion, four hundred fourteen billion, two hundred fifty-two million, two hundred fifty-five thousand, four hundred eleven".
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