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14143244433011 = 17831955554883
BaseRepresentation
bin1100110111001111101100…
…0011110111011001110011
31212002002012000121002220022
43031303323003313121303
53323210331033324021
650025152232234055
72656546532060201
oct315637303673163
955062160532808
1014143244433011
114563130850321
12170507bb3b92b
137b7918a40c95
1436c772930071
15197d718981ab
hexcdcfb0f7673

14143244433011 has 4 divisors (see below), whose sum is σ = 14975199987912. Its totient is φ = 13311288878112.

The previous prime is 14143244432987. The next prime is 14143244433029. The reversal of 14143244433011 is 11033444234141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14143244433011 is a prime.

It is a super-2 number, since 2×141432444330112 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14143244433811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 415977777425 + ... + 415977777458.

It is an arithmetic number, because the mean of its divisors is an integer number (3743799996978).

Almost surely, 214143244433011 is an apocalyptic number.

14143244433011 is a deficient number, since it is larger than the sum of its proper divisors (831955554901).

14143244433011 is an equidigital number, since it uses as much as digits as its factorization.

14143244433011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 831955554900.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 14143244433011 its reverse (11033444234141), we get a palindrome (25176688667152).

The spelling of 14143244433011 in words is "fourteen trillion, one hundred forty-three billion, two hundred forty-four million, four hundred thirty-three thousand, eleven".

Divisors: 1 17 831955554883 14143244433011