14143352605601 has 4 divisors (see below), whose sum is σ = 14280666708672. Its totient is φ = 14006038502532.

The previous prime is 14143352605583. The next prime is 14143352605621. The reversal of 14143352605601 is 10650625334141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14143352605601 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14143352605621) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68657051381 + ... + 68657051586.

It is an arithmetic number, because the mean of its divisors is an integer number (3570166677168).

Almost surely, 2^{14143352605601} is an apocalyptic number.

It is an amenable number.

14143352605601 is a deficient number, since it is larger than the sum of its proper divisors (137314103071).

14143352605601 is a wasteful number, since it uses less digits than its factorization.

14143352605601 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137314103070.

The product of its (nonzero) digits is 259200, while the sum is 41.

Adding to 14143352605601 its reverse (10650625334141), we get a palindrome (24793977939742).

The spelling of 14143352605601 in words is "fourteen trillion, one hundred forty-three billion, three hundred fifty-two million, six hundred five thousand, six hundred one".