Base | Representation |
---|---|
bin | 1100110111010000010100… |
… | …1000000011010000011110 |
3 | 1212002002121210100120000111 |
4 | 3031310011020003100132 |
5 | 3323211202301133202 |
6 | 50025221103520234 |
7 | 2656553652326404 |
oct | 315640510032036 |
9 | 55062553316014 |
10 | 14143413302302 |
11 | 4563208100319 |
12 | 17051085b907a |
13 | 7b7944a1873b |
14 | 36c78b12b474 |
15 | 197d816036d7 |
hex | cdd0520341e |
14143413302302 has 4 divisors (see below), whose sum is σ = 21215119953456. Its totient is φ = 7071706651150.
The previous prime is 14143413302299. The next prime is 14143413302303. The reversal of 14143413302302 is 20320331434141.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×141434133023022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14143413302303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3535853325574 + ... + 3535853325577.
It is an arithmetic number, because the mean of its divisors is an integer number (5303779988364).
Almost surely, 214143413302302 is an apocalyptic number.
14143413302302 is a deficient number, since it is larger than the sum of its proper divisors (7071706651154).
14143413302302 is an equidigital number, since it uses as much as digits as its factorization.
14143413302302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7071706651153.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 14143413302302 its reverse (20320331434141), we get a palindrome (34463744736443).
The spelling of 14143413302302 in words is "fourteen trillion, one hundred forty-three billion, four hundred thirteen million, three hundred two thousand, three hundred two".
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