Base | Representation |
---|---|
bin | 1000001110111000100… |
… | …0011110000011010001 |
3 | 111112001210022022020101 |
4 | 2003232020132003101 |
5 | 4304124120313441 |
6 | 144550212412401 |
7 | 13134604306624 |
oct | 2035610360321 |
9 | 445053268211 |
10 | 141434151121 |
11 | 54a889890aa |
12 | 234b2017101 |
13 | 1044ca3a023 |
14 | 6bb9caddbb |
15 | 3a2bab0231 |
hex | 20ee21e0d1 |
141434151121 has 2 divisors, whose sum is σ = 141434151122. Its totient is φ = 141434151120.
The previous prime is 141434151119. The next prime is 141434151127. The reversal of 141434151121 is 121151434141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91397382400 + 50036768721 = 302320^2 + 223689^2 .
It is a cyclic number.
It is not a de Polignac number, because 141434151121 - 21 = 141434151119 is a prime.
Together with 141434151119, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 141434151121.
It is not a weakly prime, because it can be changed into another prime (141434151127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70717075560 + 70717075561.
It is an arithmetic number, because the mean of its divisors is an integer number (70717075561).
Almost surely, 2141434151121 is an apocalyptic number.
It is an amenable number.
141434151121 is a deficient number, since it is larger than the sum of its proper divisors (1).
141434151121 is an equidigital number, since it uses as much as digits as its factorization.
141434151121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1920, while the sum is 28.
Adding to 141434151121 its reverse (121151434141), we get a palindrome (262585585262).
The spelling of 141434151121 in words is "one hundred forty-one billion, four hundred thirty-four million, one hundred fifty-one thousand, one hundred twenty-one".
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