Base | Representation |
---|---|
bin | 1100110111010000101001… |
… | …0011100110001111001001 |
3 | 1212002002211211220012011020 |
4 | 3031310022103212033021 |
5 | 3323211342023341431 |
6 | 50025233450423053 |
7 | 2656556056144035 |
oct | 315641223461711 |
9 | 55062754805136 |
10 | 14143500215241 |
11 | 45632521732a1 |
12 | 1705131731a89 |
13 | 7b7959a29507 |
14 | 36c7988b31c5 |
15 | 197d89070696 |
hex | cdd0a4e63c9 |
14143500215241 has 8 divisors (see below), whose sum is σ = 19677913343040. Its totient is φ = 9019043615472.
The previous prime is 14143500215213. The next prime is 14143500215267. The reversal of 14143500215241 is 14251200534141.
14143500215241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14143500215241 - 213 = 14143500207049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14143500215291) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102489131926 + ... + 102489132063.
It is an arithmetic number, because the mean of its divisors is an integer number (2459739167880).
Almost surely, 214143500215241 is an apocalyptic number.
It is an amenable number.
14143500215241 is a deficient number, since it is larger than the sum of its proper divisors (5534413127799).
14143500215241 is a wasteful number, since it uses less digits than its factorization.
14143500215241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204978264015.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 14143500215241 its reverse (14251200534141), we get a palindrome (28394700749382).
The spelling of 14143500215241 in words is "fourteen trillion, one hundred forty-three billion, five hundred million, two hundred fifteen thousand, two hundred forty-one".
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