1414350433051 has 4 divisors (see below), whose sum is σ = 1414368570672. Its totient is φ = 1414332295432.

The previous prime is 1414350433039. The next prime is 1414350433057. The reversal of 1414350433051 is 1503340534141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1414350433051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1414350432998 and 1414350433016.

It is not an unprimeable number, because it can be changed into a prime (1414350433057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8951335 + ... + 9107968.

It is an arithmetic number, because the mean of its divisors is an integer number (353592142668).

Almost surely, 2^{1414350433051} is an apocalyptic number.

1414350433051 is a deficient number, since it is larger than the sum of its proper divisors (18137621).

1414350433051 is an equidigital number, since it uses as much as digits as its factorization.

1414350433051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18137620.

The product of its (nonzero) digits is 43200, while the sum is 34.

Adding to 1414350433051 its reverse (1503340534141), we get a palindrome (2917690967192).

The spelling of 1414350433051 in words is "one trillion, four hundred fourteen billion, three hundred fifty million, four hundred thirty-three thousand, fifty-one".