1414431324001 has 4 divisors (see below), whose sum is σ = 1475928338112. Its totient is φ = 1352934309892.

The previous prime is 1414431323969. The next prime is 1414431324017. The reversal of 1414431324001 is 1004231344141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1414431324001 - 2⁵ = 1414431323969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1414431324041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30748507021 + ... + 30748507066.

It is an arithmetic number, because the mean of its divisors is an integer number (368982084528).

Almost surely, 2^{1414431324001} is an apocalyptic number.

It is an amenable number.

1414431324001 is a deficient number, since it is larger than the sum of its proper divisors (61497014111).

1414431324001 is an equidigital number, since it uses as much as digits as its factorization.

1414431324001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61497014110.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1414431324001 its reverse (1004231344141), we get a palindrome (2418662668142).

The spelling of 1414431324001 in words is "one trillion, four hundred fourteen billion, four hundred thirty-one million, three hundred twenty-four thousand, one".