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141444102301 = 253155884671
BaseRepresentation
bin1000001110111010111…
…0011011100010011101
3111112002111000212200121
42003232232123202131
54304134142233201
6144551205554541
713135055014045
oct2035656334235
9445074025617
10141444102301
1154a93565617
12234b5415a51
1310451b125b8
146bbb340725
153a2c8c89a1
hex20eeb9b89d

141444102301 has 4 divisors (see below), whose sum is σ = 141499989504. Its totient is φ = 141388215100.

The previous prime is 141444102281. The next prime is 141444102361. The reversal of 141444102301 is 103201444141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141444102301 - 29 = 141444101789 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141444102361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27939805 + ... + 27944866.

It is an arithmetic number, because the mean of its divisors is an integer number (35374997376).

Almost surely, 2141444102301 is an apocalyptic number.

It is an amenable number.

141444102301 is a deficient number, since it is larger than the sum of its proper divisors (55887203).

141444102301 is an equidigital number, since it uses as much as digits as its factorization.

141444102301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55887202.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 141444102301 its reverse (103201444141), we get a palindrome (244645546442).

The spelling of 141444102301 in words is "one hundred forty-one billion, four hundred forty-four million, one hundred two thousand, three hundred one".

Divisors: 1 2531 55884671 141444102301