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14144515241 is a prime number
BaseRepresentation
bin11010010110001010…
…00010110010101001
31100111202101211012212
431023011002302221
5212431443441431
610255314014505
71010341252523
oct151305026251
940452354185
1014144515241
115aa923471a
1228a8b77435
13144553a45c
14982774a13
1557bb7c72b
hex34b142ca9

14144515241 has 2 divisors, whose sum is σ = 14144515242. Its totient is φ = 14144515240.

The previous prime is 14144515181. The next prime is 14144515243. The reversal of 14144515241 is 14251544141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11972955241 + 2171560000 = 109421^2 + 46600^2 .

It is a cyclic number.

It is not a de Polignac number, because 14144515241 - 226 = 14077406377 is a prime.

It is a super-2 number, since 2×141445152412 (a number of 21 digits) contains 22 as substring.

Together with 14144515243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14144515198 and 14144515207.

It is not a weakly prime, because it can be changed into another prime (14144515243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072257620 + 7072257621.

It is an arithmetic number, because the mean of its divisors is an integer number (7072257621).

Almost surely, 214144515241 is an apocalyptic number.

It is an amenable number.

14144515241 is a deficient number, since it is larger than the sum of its proper divisors (1).

14144515241 is an equidigital number, since it uses as much as digits as its factorization.

14144515241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12800, while the sum is 32.

The spelling of 14144515241 in words is "fourteen billion, one hundred forty-four million, five hundred fifteen thousand, two hundred forty-one".