Base | Representation |
---|---|
bin | 11010010110010001… |
… | …00100110101011001 |
3 | 1100111211010212021102 |
4 | 31023020210311121 |
5 | 212432213103423 |
6 | 10255345521145 |
7 | 1010352160046 |
oct | 151310446531 |
9 | 40454125242 |
10 | 14145441113 |
11 | 5aa9807301 |
12 | 28a93431b5 |
13 | 14457a29cb |
14 | 9829361cd |
15 | 57bcb1c28 |
hex | 34b224d59 |
14145441113 has 4 divisors (see below), whose sum is σ = 14218733748. Its totient is φ = 14072148480.
The previous prime is 14145441109. The next prime is 14145441131. The reversal of 14145441113 is 31114454141.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31114454141 = 37 ⋅840931193.
It can be written as a sum of positive squares in 2 ways, for example, as 8997091609 + 5148349504 = 94853^2 + 71752^2 .
It is a cyclic number.
It is not a de Polignac number, because 14145441113 - 22 = 14145441109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14145441133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36646028 + ... + 36646413.
It is an arithmetic number, because the mean of its divisors is an integer number (3554683437).
Almost surely, 214145441113 is an apocalyptic number.
It is an amenable number.
14145441113 is a deficient number, since it is larger than the sum of its proper divisors (73292635).
14145441113 is an equidigital number, since it uses as much as digits as its factorization.
14145441113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73292634.
The product of its digits is 3840, while the sum is 29.
Adding to 14145441113 its reverse (31114454141), we get a palindrome (45259895254).
The spelling of 14145441113 in words is "fourteen billion, one hundred forty-five million, four hundred forty-one thousand, one hundred thirteen".
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