14150003411323 has 4 divisors (see below), whose sum is σ = 15238465212208. Its totient is φ = 13061541610440.

The previous prime is 14150003411231. The next prime is 14150003411359. The reversal of 14150003411323 is 32311430005141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14150003411323 - 2⁹ = 14150003410811 is a prime.

It is a super-2 number, since 2×14150003411323² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14150003411291 and 14150003411300.

It is not an unprimeable number, because it can be changed into a prime (14150003411123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 544230900423 + ... + 544230900448.

It is an arithmetic number, because the mean of its divisors is an integer number (3809616303052).

Almost surely, 2^{14150003411323} is an apocalyptic number.

14150003411323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14150003411323 is a deficient number, since it is larger than the sum of its proper divisors (1088461800885).

14150003411323 is a wasteful number, since it uses less digits than its factorization.

14150003411323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1088461800884.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 14150003411323 its reverse (32311430005141), we get a palindrome (46461433416464).

The spelling of 14150003411323 in words is "fourteen trillion, one hundred fifty billion, three million, four hundred eleven thousand, three hundred twenty-three".