Base | Representation |
---|---|
bin | 100000001011000110010111… |
… | …010000011111100110000101 |
3 | 200120000021211200112121201200 |
4 | 200023012113100133212011 |
5 | 122021314440211000203 |
6 | 1220540151035013113 |
7 | 41543024511354621 |
oct | 4013062720374605 |
9 | 616007750477650 |
10 | 141500235250053 |
11 | 410a4a04993469 |
12 | 13a5383a59a199 |
13 | 60c55517a3b04 |
14 | 26d290dcb4181 |
15 | 1155b2c3549a3 |
hex | 80b19741f985 |
141500235250053 has 6 divisors (see below), whose sum is σ = 204389228694534. Its totient is φ = 94333490166696.
The previous prime is 141500235250037. The next prime is 141500235250069. The reversal of 141500235250053 is 350052532005141.
141500235250053 is a `hidden beast` number, since 1 + 4 + 1 + 50 + 0 + 2 + 3 + 52 + 500 + 53 = 666.
It is an interprime number because it is at equal distance from previous prime (141500235250037) and next prime (141500235250069).
It can be written as a sum of positive squares in only one way, i.e., 136469895013089 + 5030340236964 = 11682033^2 + 2242842^2 .
It is not a de Polignac number, because 141500235250053 - 24 = 141500235250037 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141500235250453) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7861124180550 + ... + 7861124180567.
It is an arithmetic number, because the mean of its divisors is an integer number (34064871449089).
Almost surely, 2141500235250053 is an apocalyptic number.
It is an amenable number.
141500235250053 is a deficient number, since it is larger than the sum of its proper divisors (62888993444481).
141500235250053 is a wasteful number, since it uses less digits than its factorization.
141500235250053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15722248361123 (or 15722248361120 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 141500235250053 its reverse (350052532005141), we get a palindrome (491552767255194).
The spelling of 141500235250053 in words is "one hundred forty-one trillion, five hundred billion, two hundred thirty-five million, two hundred fifty thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •