1415140011113 has 4 divisors (see below), whose sum is σ = 1415145430608. Its totient is φ = 1415134591620.

The previous prime is 1415140011097. The next prime is 1415140011119. The reversal of 1415140011113 is 3111100415141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1415140011113 - 2⁴ = 1415140011097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1415140011119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2297123 + ... + 2847288.

It is an arithmetic number, because the mean of its divisors is an integer number (353786357652).

Almost surely, 2^{1415140011113} is an apocalyptic number.

It is an amenable number.

1415140011113 is a deficient number, since it is larger than the sum of its proper divisors (5419495).

1415140011113 is an equidigital number, since it uses as much as digits as its factorization.

1415140011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5419494.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 1415140011113 its reverse (3111100415141), we get a palindrome (4526240426254).

The spelling of 1415140011113 in words is "one trillion, four hundred fifteen billion, one hundred forty million, eleven thousand, one hundred thirteen".