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1415170160117 = 7202167165731
BaseRepresentation
bin10100100101111110101…
…101101111010111110101
312000021210122022202221222
4110211332231233113311
5141141232030110432
63002041543520125
7204146143613060
oct24457655572765
95007718282858
101415170160117
114a61967310aa
121aa329759045
13a35b079008c
144c6cd2858d7
1526c29d87112
hex1497eb6f5f5

1415170160117 has 4 divisors (see below), whose sum is σ = 1617337325856. Its totient is φ = 1213002994380.

The previous prime is 1415170160113. The next prime is 1415170160167. The reversal of 1415170160117 is 7110610715141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1415170160117 - 22 = 1415170160113 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1415170160113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101083582859 + ... + 101083582872.

It is an arithmetic number, because the mean of its divisors is an integer number (404334331464).

Almost surely, 21415170160117 is an apocalyptic number.

It is an amenable number.

1415170160117 is a deficient number, since it is larger than the sum of its proper divisors (202167165739).

1415170160117 is an equidigital number, since it uses as much as digits as its factorization.

1415170160117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 202167165738.

The product of its (nonzero) digits is 5880, while the sum is 35.

Adding to 1415170160117 its reverse (7110610715141), we get a palindrome (8525780875258).

The spelling of 1415170160117 in words is "one trillion, four hundred fifteen billion, one hundred seventy million, one hundred sixty thousand, one hundred seventeen".

Divisors: 1 7 202167165731 1415170160117