Base | Representation |
---|---|
bin | 11010010111001011… |
… | …00010100110000001 |
3 | 1100112100102121220122 |
4 | 31023211202212001 |
5 | 212441134042423 |
6 | 10300220350025 |
7 | 1010503543061 |
oct | 151345424601 |
9 | 40470377818 |
10 | 14153034113 |
11 | 6003023009 |
12 | 28ab9a5315 |
13 | 1447230aca |
14 | 9839513a1 |
15 | 57c7b18c8 |
hex | 34b962981 |
14153034113 has 4 divisors (see below), whose sum is σ = 14154622128. Its totient is φ = 14151446100.
The previous prime is 14153034109. The next prime is 14153034143. The reversal of 14153034113 is 31143035141.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31143035141 = 22447 ⋅1387403.
It is a cyclic number.
It is not a de Polignac number, because 14153034113 - 22 = 14153034109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14153034143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 780563 + ... + 798488.
It is an arithmetic number, because the mean of its divisors is an integer number (3538655532).
Almost surely, 214153034113 is an apocalyptic number.
It is an amenable number.
14153034113 is a deficient number, since it is larger than the sum of its proper divisors (1588015).
14153034113 is an equidigital number, since it uses as much as digits as its factorization.
14153034113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1588014.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 14153034113 its reverse (31143035141), we get a palindrome (45296069254).
The spelling of 14153034113 in words is "fourteen billion, one hundred fifty-three million, thirty-four thousand, one hundred thirteen".
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