14153444131 has 4 divisors (see below), whose sum is σ = 14168680200. Its totient is φ = 14138208064.

The previous prime is 14153444089. The next prime is 14153444141. The reversal of 14153444131 is 13144435141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13144435141 = 661 ⋅19885681.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14153444131 is a prime.

It is a super-2 number, since 2×14153444131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14153444093 and 14153444102.

It is not an unprimeable number, because it can be changed into a prime (14153444141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7616641 + ... + 7618498.

It is an arithmetic number, because the mean of its divisors is an integer number (3542170050).

Almost surely, 2^14153444131 is an apocalyptic number.

14153444131 is a deficient number, since it is larger than the sum of its proper divisors (15236069).

14153444131 is an equidigital number, since it uses as much as digits as its factorization.

14153444131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15236068.

The product of its digits is 11520, while the sum is 31.

Adding to 14153444131 its reverse (13144435141), we get a palindrome (27297879272).

The spelling of 14153444131 in words is "fourteen billion, one hundred fifty-three million, four hundred forty-four thousand, one hundred thirty-one".