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14153666141 = 32479435779
BaseRepresentation
bin11010010111001111…
…11100111001011101
31100112101121201220002
431023213330321131
5212441314304031
610300242104045
71010512114526
oct151347747135
940471551802
1014153666141
11600341494a
1228b004b025
1314473c26a4
14983a7784d
1557c888ccb
hex34b9fce5d

14153666141 has 4 divisors (see below), whose sum is σ = 14154134400. Its totient is φ = 14153197884.

The previous prime is 14153666119. The next prime is 14153666159. The reversal of 14153666141 is 14166635141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14153666141 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14153666095 and 14153666104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14153666341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185411 + ... + 250368.

It is an arithmetic number, because the mean of its divisors is an integer number (3538533600).

Almost surely, 214153666141 is an apocalyptic number.

It is an amenable number.

14153666141 is a deficient number, since it is larger than the sum of its proper divisors (468259).

14153666141 is an equidigital number, since it uses as much as digits as its factorization.

14153666141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 468258.

The product of its digits is 51840, while the sum is 38.

The spelling of 14153666141 in words is "fourteen billion, one hundred fifty-three million, six hundred sixty-six thousand, one hundred forty-one".

Divisors: 1 32479 435779 14153666141