1415441153413 has 4 divisors (see below), whose sum is σ = 1617647032480. Its totient is φ = 1213235274348.

The previous prime is 1415441153381. The next prime is 1415441153449. The reversal of 1415441153413 is 3143511445141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1415441153413 - 2⁵ = 1415441153381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1415441153453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101102939523 + ... + 101102939536.

It is an arithmetic number, because the mean of its divisors is an integer number (404411758120).

Almost surely, 2^{1415441153413} is an apocalyptic number.

It is an amenable number.

1415441153413 is a deficient number, since it is larger than the sum of its proper divisors (202205879067).

1415441153413 is an equidigital number, since it uses as much as digits as its factorization.

1415441153413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 202205879066.

The product of its digits is 57600, while the sum is 37.

Adding to 1415441153413 its reverse (3143511445141), we get a palindrome (4558952598554).

The spelling of 1415441153413 in words is "one trillion, four hundred fifteen billion, four hundred forty-one million, one hundred fifty-three thousand, four hundred thirteen".