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141547612133 is a prime number
BaseRepresentation
bin1000001111010011100…
…1010010011111100101
3111112100200210201111002
42003310321102133211
54304342142042013
6145005344323045
713140452565014
oct2036471223745
9445320721432
10141547612133
1155036a34034
1223524013485
131046a3b4815
146bcada6a7b
153a36a23358
hex20f4e527e5

141547612133 has 2 divisors, whose sum is σ = 141547612134. Its totient is φ = 141547612132.

The previous prime is 141547612127. The next prime is 141547612153. The reversal of 141547612133 is 331216745141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139485816484 + 2061795649 = 373478^2 + 45407^2 .

It is an emirp because it is prime and its reverse (331216745141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141547612133 - 210 = 141547611109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141547612153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70773806066 + 70773806067.

It is an arithmetic number, because the mean of its divisors is an integer number (70773806067).

Almost surely, 2141547612133 is an apocalyptic number.

It is an amenable number.

141547612133 is a deficient number, since it is larger than the sum of its proper divisors (1).

141547612133 is an equidigital number, since it uses as much as digits as its factorization.

141547612133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480, while the sum is 38.

The spelling of 141547612133 in words is "one hundred forty-one billion, five hundred forty-seven million, six hundred twelve thousand, one hundred thirty-three".