Search a number
-
+
14155410453 = 34718470151
BaseRepresentation
bin11010010111011101…
…00110110000010101
31100112111220100122020
431023232212300111
5212442241113303
610300343323353
71010533001142
oct151356466025
940474810566
1014155410453
1160043a6428
1228b0750559
131447883622
14983dad3c9
1557cad0a53
hex34bba6c15

14155410453 has 4 divisors (see below), whose sum is σ = 18873880608. Its totient is φ = 9436940300.

The previous prime is 14155410427. The next prime is 14155410491. The reversal of 14155410453 is 35401455141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14155410453 - 214 = 14155394069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14155410403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2359235073 + ... + 2359235078.

It is an arithmetic number, because the mean of its divisors is an integer number (4718470152).

Almost surely, 214155410453 is an apocalyptic number.

It is an amenable number.

14155410453 is a deficient number, since it is larger than the sum of its proper divisors (4718470155).

14155410453 is an equidigital number, since it uses as much as digits as its factorization.

14155410453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4718470154.

The product of its (nonzero) digits is 24000, while the sum is 33.

Adding to 14155410453 its reverse (35401455141), we get a palindrome (49556865594).

The spelling of 14155410453 in words is "fourteen billion, one hundred fifty-five million, four hundred ten thousand, four hundred fifty-three".

Divisors: 1 3 4718470151 14155410453