Base | Representation |
---|---|
bin | 11010010111011110… |
… | …00010000010110111 |
3 | 1100112112010000222011 |
4 | 31023233002002313 |
5 | 212442303202411 |
6 | 10300345545051 |
7 | 1010533645054 |
oct | 151357020267 |
9 | 40475100864 |
10 | 14155522231 |
11 | 6004472404 |
12 | 28b07a5187 |
13 | 14478c2476 |
14 | 983ddc02b |
15 | 57cb03c21 |
hex | 34bbc20b7 |
14155522231 has 2 divisors, whose sum is σ = 14155522232. Its totient is φ = 14155522230.
The previous prime is 14155522223. The next prime is 14155522237. The reversal of 14155522231 is 13222555141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14155522231 - 23 = 14155522223 is a prime.
It is a super-2 number, since 2×141555222312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14155522193 and 14155522202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14155522237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7077761115 + 7077761116.
It is an arithmetic number, because the mean of its divisors is an integer number (7077761116).
Almost surely, 214155522231 is an apocalyptic number.
14155522231 is a deficient number, since it is larger than the sum of its proper divisors (1).
14155522231 is an equidigital number, since it uses as much as digits as its factorization.
14155522231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12000, while the sum is 31.
The spelling of 14155522231 in words is "fourteen billion, one hundred fifty-five million, five hundred twenty-two thousand, two hundred thirty-one".
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