14155533142111 has 4 divisors (see below), whose sum is σ = 14166396944752. Its totient is φ = 14144669339472.

The previous prime is 14155533142073. The next prime is 14155533142139. The reversal of 14155533142111 is 11124133555141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14155533142111 - 2⁹ = 14155533141599 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14155533142171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5431899366 + ... + 5431901971.

It is an arithmetic number, because the mean of its divisors is an integer number (3541599236188).

Almost surely, 2^{14155533142111} is an apocalyptic number.

14155533142111 is a deficient number, since it is larger than the sum of its proper divisors (10863802641).

14155533142111 is a wasteful number, since it uses less digits than its factorization.

14155533142111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10863802640.

The product of its digits is 36000, while the sum is 37.

Adding to 14155533142111 its reverse (11124133555141), we get a palindrome (25279666697252).

The spelling of 14155533142111 in words is "fourteen trillion, one hundred fifty-five billion, five hundred thirty-three million, one hundred forty-two thousand, one hundred eleven".