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14155545075493 is a prime number
BaseRepresentation
bin1100110111111101100000…
…1111000101111100100101
31212010020221021102111012111
43031333120033011330211
53323411024014403433
650034545001521021
72660463413600503
oct315773017057445
955106837374174
1014155545075493
114568373185058
1217075334a3171
137b8b29269b63
1436d1bc44b673
15198341702dcd
hexcdfd83c5f25

14155545075493 has 2 divisors, whose sum is σ = 14155545075494. Its totient is φ = 14155545075492.

The previous prime is 14155545075437. The next prime is 14155545075557. The reversal of 14155545075493 is 39457054555141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11319308478724 + 2836236596769 = 3364418^2 + 1684113^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14155545075493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14155545075403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7077772537746 + 7077772537747.

It is an arithmetic number, because the mean of its divisors is an integer number (7077772537747).

Almost surely, 214155545075493 is an apocalyptic number.

It is an amenable number.

14155545075493 is a deficient number, since it is larger than the sum of its proper divisors (1).

14155545075493 is an equidigital number, since it uses as much as digits as its factorization.

14155545075493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800000, while the sum is 58.

The spelling of 14155545075493 in words is "fourteen trillion, one hundred fifty-five billion, five hundred forty-five million, seventy-five thousand, four hundred ninety-three".