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1416435613001 = 2361584157087
BaseRepresentation
bin10100100111001010001…
…001000011110101001001
312000102001211111102222022
4110213022021003311021
5141201330004104001
63002411310534225
7204222411026063
oct24471211036511
95012054442868
101416435613001
114a6785a82632
121aa621507375
13a37529c0476
144c7ad372733
1526ca100111b
hex149ca243d49

1416435613001 has 4 divisors (see below), whose sum is σ = 1478019770112. Its totient is φ = 1354851455892.

The previous prime is 1416435612973. The next prime is 1416435613037. The reversal of 1416435613001 is 1003165346141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1416435613001 - 230 = 1415361871177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1416435673001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30792078521 + ... + 30792078566.

It is an arithmetic number, because the mean of its divisors is an integer number (369504942528).

Almost surely, 21416435613001 is an apocalyptic number.

It is an amenable number.

1416435613001 is a deficient number, since it is larger than the sum of its proper divisors (61584157111).

1416435613001 is an equidigital number, since it uses as much as digits as its factorization.

1416435613001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61584157110.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 1416435613001 in words is "one trillion, four hundred sixteen billion, four hundred thirty-five million, six hundred thirteen thousand, one".

Divisors: 1 23 61584157087 1416435613001