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14165656103 = 14879952057
BaseRepresentation
bin11010011000101011…
…01100001000100111
31100120020011220000202
431030111230020213
5213002401443403
610301351101115
71011016042634
oct151425541047
940506156022
1014165656103
11600a164105
1228b407179b
131449a2cc41
149854b918b
1557d956688
hex34c56c227

14165656103 has 4 divisors (see below), whose sum is σ = 14166623040. Its totient is φ = 14164689168.

The previous prime is 14165656069. The next prime is 14165656159. The reversal of 14165656103 is 30165656141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14165656103 - 210 = 14165655079 is a prime.

It is a super-2 number, since 2×141656561032 (a number of 21 digits) contains 22 as substring.

It is an alternating number because its digits alternate between odd and even.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14165656003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 461150 + ... + 490907.

It is an arithmetic number, because the mean of its divisors is an integer number (3541655760).

Almost surely, 214165656103 is an apocalyptic number.

14165656103 is a deficient number, since it is larger than the sum of its proper divisors (966937).

14165656103 is an equidigital number, since it uses as much as digits as its factorization.

14165656103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 966936.

The product of its (nonzero) digits is 64800, while the sum is 38.

Adding to 14165656103 its sum of digits (38), we get a palindrome (14165656141).

The spelling of 14165656103 in words is "fourteen billion, one hundred sixty-five million, six hundred fifty-six thousand, one hundred three".

Divisors: 1 14879 952057 14165656103