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14174051117 is a prime number
BaseRepresentation
bin11010011001101011…
…01101101100101101
31100120210222101211012
431030311231230231
5213012024113432
610302251035005
71011150306122
oct151465555455
940523871735
1014174051117
116013978436
1228b6a3ba65
13144b6ac0c5
14986662749
1557e563cb2
hex34cd6db2d

14174051117 has 2 divisors, whose sum is σ = 14174051118. Its totient is φ = 14174051116.

The previous prime is 14174051113. The next prime is 14174051173. The reversal of 14174051117 is 71115047141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13143705316 + 1030345801 = 114646^2 + 32099^2 .

It is an emirp because it is prime and its reverse (71115047141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14174051117 - 22 = 14174051113 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14174051113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7087025558 + 7087025559.

It is an arithmetic number, because the mean of its divisors is an integer number (7087025559).

Almost surely, 214174051117 is an apocalyptic number.

It is an amenable number.

14174051117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14174051117 is an equidigital number, since it uses as much as digits as its factorization.

14174051117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3920, while the sum is 32.

Adding to 14174051117 its reverse (71115047141), we get a palindrome (85289098258).

The spelling of 14174051117 in words is "fourteen billion, one hundred seventy-four million, fifty-one thousand, one hundred seventeen".