Base | Representation |
---|---|
bin | 11010011001101011… |
… | …01101101100101101 |
3 | 1100120210222101211012 |
4 | 31030311231230231 |
5 | 213012024113432 |
6 | 10302251035005 |
7 | 1011150306122 |
oct | 151465555455 |
9 | 40523871735 |
10 | 14174051117 |
11 | 6013978436 |
12 | 28b6a3ba65 |
13 | 144b6ac0c5 |
14 | 986662749 |
15 | 57e563cb2 |
hex | 34cd6db2d |
14174051117 has 2 divisors, whose sum is σ = 14174051118. Its totient is φ = 14174051116.
The previous prime is 14174051113. The next prime is 14174051173. The reversal of 14174051117 is 71115047141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13143705316 + 1030345801 = 114646^2 + 32099^2 .
It is an emirp because it is prime and its reverse (71115047141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14174051117 - 22 = 14174051113 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14174051113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7087025558 + 7087025559.
It is an arithmetic number, because the mean of its divisors is an integer number (7087025559).
Almost surely, 214174051117 is an apocalyptic number.
It is an amenable number.
14174051117 is a deficient number, since it is larger than the sum of its proper divisors (1).
14174051117 is an equidigital number, since it uses as much as digits as its factorization.
14174051117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3920, while the sum is 32.
Adding to 14174051117 its reverse (71115047141), we get a palindrome (85289098258).
The spelling of 14174051117 in words is "fourteen billion, one hundred seventy-four million, fifty-one thousand, one hundred seventeen".
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