14194054695971 has 2 divisors, whose sum is σ = 14194054695972. Its totient is φ = 14194054695970.

The previous prime is 14194054695907. The next prime is 14194054695973. The reversal of 14194054695971 is 17959645049141.

14194054695971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14194054695971 - 2⁶ = 14194054695907 is a prime.

Together with 14194054695973, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14194054695898 and 14194054695907.

It is not a weakly prime, because it can be changed into another prime (14194054695973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7097027347985 + 7097027347986.

It is an arithmetic number, because the mean of its divisors is an integer number (7097027347986).

Almost surely, 2^{14194054695971} is an apocalyptic number.

14194054695971 is a deficient number, since it is larger than the sum of its proper divisors (1).

14194054695971 is an equidigital number, since it uses as much as digits as its factorization.

14194054695971 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48988800, while the sum is 65.

The spelling of 14194054695971 in words is "fourteen trillion, one hundred ninety-four billion, fifty-four million, six hundred ninety-five thousand, nine hundred seventy-one".