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14200000753 is a prime number
BaseRepresentation
bin11010011100110001…
…01101000011110001
31100122121210210000211
431032120231003301
5213040200011003
610305015144121
71011614005051
oct151630550361
940577723024
1014200000753
116027591814
122903675041
131453b96613
14989c99561
1558198c96d
hex34e62d0f1

14200000753 has 2 divisors, whose sum is σ = 14200000754. Its totient is φ = 14200000752.

The previous prime is 14200000741. The next prime is 14200000853. The reversal of 14200000753 is 35700000241.

14200000753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12930646369 + 1269354384 = 113713^2 + 35628^2 .

It is a cyclic number.

It is not a de Polignac number, because 14200000753 - 213 = 14199992561 is a prime.

It is a super-3 number, since 3×142000007533 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14200000733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7100000376 + 7100000377.

It is an arithmetic number, because the mean of its divisors is an integer number (7100000377).

Almost surely, 214200000753 is an apocalyptic number.

It is an amenable number.

14200000753 is a deficient number, since it is larger than the sum of its proper divisors (1).

14200000753 is an equidigital number, since it uses as much as digits as its factorization.

14200000753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 22.

Adding to 14200000753 its reverse (35700000241), we get a palindrome (49900000994).

The spelling of 14200000753 in words is "fourteen billion, two hundred million, seven hundred fifty-three", and thus it is an aban number.